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Amplitude and Period of Sine and Cosine Functions

Chapter 42

Amplitude and Period of Sine and Cosine Functions Concept Explanation

The Amplitude of a sine or cosine function represents the maximum displacement from the equilibrium (midline) of the wave. It is the vertical stretch or compression of the graph. The amplitude is given by ( |A| ) in the equation  y = A \sin(Bx) or   y = A \cos(Bx) .

The Period refers to the distance (along the x-axis) over which the function completes one full cycle. For sine and cosine functions, the period is calculated using the formula:

\text{Period} = \frac{2\pi}{|B|}

where ( B ) is the coefficient of ( x ) in the function.

*** QuickLaTeX cannot compile formula:
\begin{tikzpicture}\begin{axis}[axis x line=middle,axis y line=middle,samples=100,xmin=-2<em>pi, xmax=2</em>pi,ymin=-2, ymax=2,xlabel={$x$}, ylabel={$y$},domain=-2<em>pi:2</em>pi,width=10cm,height=5cm]\addplot [blue, thick] {sin(deg(x))};\end{axis}\end{tikzpicture}

*** Error message:
Package PGF Math Error: Unknown function `em' (in '-2<em>pi').
leading text: ...n=-2<em>pi:2</em>pi,width=10cm,height=5cm]
Package PGF Math Error: Could not parse input '' as a floating point number, sorry. The unreadable part was near ''. (in '2</em>pi').
leading text: ...n=-2<em>pi:2</em>pi,width=10cm,height=5cm]
Package PGF Math Error: Unknown function `em' (in '2</em>pi').
leading text: ...n=-2<em>pi:2</em>pi,width=10cm,height=5cm]
Package PGF Math Error: Unknown function `em' (in '-2<em>pi').
leading text: ...=5cm]\addplot [blue, thick] {sin(deg(x))};
Package PGF Math Error: Could not parse input '' as a floating point number, sorry. The unreadable part was near ''. (in '2</em>pi').
leading text: ...=5cm]\addplot [blue, thick] {sin(deg(x))};
Package PGF Math Error: Unknown function `em' (in '2</em>pi').

In the graph above, the amplitude is 1, and the period is  2\pi .

Common Mistakes:

  1. Confusing Amplitude with Period: Some students mistakenly associate the period with the vertical stretch.
  2. Forgetting Absolute Value: When calculating the amplitude, always take the absolute value of ( A ).

Helpful Tips:

  • Use the Graph to Visualize: Plot the sine or cosine graph to clearly see the amplitude and period.
  • Remember the Formula: Use   \text{Period} = \frac{2\pi}{|B|} to calculate the period.

Hard Questions:

Q1: For the function  y = 3 \sin(2x) , find the amplitude and period.

Step-by-Step Solution:

  1. The amplitude is  |A| = 3 .
  2. The period is:
    \text{Period} = \frac{2\pi}{|B|} = \frac{2\pi}{2} = \pi

Answer:

  • Amplitude: 3
  • Period:  \pi

Q2: For the function  y = -4 \cos\left(\frac{x}{3}\right) , determine the amplitude and period.

Step-by-Step Solution:

  1. The amplitude is  |A| = 4 (the negative sign affects the direction, but not the amplitude).
  2. The period is:
    \text{Period} = \frac{2\pi}{|B|} = \frac{2\pi}{\frac{1}{3}} = 6\pi

Answer:

  • Amplitude: 4
  • Period:  6\pi

Q3: What is the amplitude and period of the function  y = 0.5 \sin(5x) ?

Step-by-Step Solution:

  1. The amplitude is  |A| = 0.5
  2. The period is:
     \text{Period} = \frac{2\pi}{5}

Answer:

  • Amplitude: 0.5
  • Period:   \frac {2\pi}{5}

Q4: For the function   y = 2 \cos(4x) , find the amplitude and period.

Step-by-Step Solution:

  1. The amplitude is   |A| = 2 .
  2. The period is:
     \text{Period} = \frac{2\pi}{4} = \frac{\pi}{2}

Answer:

  • Amplitude: 2
  • Period:  \frac{\pi}{2}

Q5: For the function   y = -\frac{3}{2} \sin(6x) , calculate the amplitude and period.

Step-by-Step Solution:

  1. The amplitude is   |A| = \frac{3}{2}
  2. The period is:
     \text{Period} = \frac{2\pi}{6} = \frac{\pi}{3}

Answer:

  • Amplitude:   \frac{3}{2}
  • Period:   \frac{\pi}{3}

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